10x+4y+11xy
open circle on +2, arrow going right.
4
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
4y + 7 < 3y + 9 4y - 3y < 9 - 7 y < 2
4y > 16 divide by 6 both sides; y > 4 This inequality is true for all y greater than 4 (4 is not a solution).
10x+4y+11xy
They are two regions of the Cartesian plane with the straight line 3x + 4y = 12 defining their boundary. That line is not part of either region.
open circle on +2, arrow going right.
plot 4y then 3x
4y + 10 = 22 4y - 10 - 10 4y=12 4y 4y 4y=3
4
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
We cannot say anything because the value of x and y can be any thing. if x and y are 4,0 or 0,3 respectively then it is equal.But u can find many such values for 3x+4y=12.there are infinite values for 3x+4y<12 and 3x+4y>12
4y + 7 < 3y + 9 4y - 3y < 9 - 7 y < 2
8y - 38
5