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Until you become expert at this I suggest you do this in two stages (using c and d separately).
Suppose there are c digits after the decimal place where the digits are non-repeating, and followed by a repeating pattern of a string of d digits. Then the numerator is the old original string including one lot of the repeated digits minus the original string with none of the repeating digits. The denominator is 10^c*(10^d - 1), which is a string of d 9s followed by c 0s.
For example
123.26159159… There are 2 digits, "26", after the decimal point before the repeats kick in so c = 2, and the repeating string "159" is 3 digits long so d = 3.
So the numerator is 12326159 – 12326 = 12313833
and the denominator is 99900
Therefore the fraction is 12313833/99900.
Wiki User
∙ 6y ago
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