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How do you Find the equation of a parabola with the vertex x equals -2 y equals -5 and passes through x equals 4 y equals -1?
Wiki User
∙ 12y ago
(X +2)^2 - 5 = 0
X = - 4, Y = - 1
--------------------------- for intercepts
Just read it.
y = x2 +4x -1 (the standard form)
Since the vertex is (-2, -5), x = -2 is the equation of the axis of symmetry, also b= 4a (-b/2a = -2).
Since the parabola passes through (-4, -1) it also will passes through (0, -1), it means that c (y-intercept) equals to -1.
So we have,
y = ax2 + 4ax - 1 (replace x with -2, and y with -5)
-5 = 4a - 8a - 1
-4 = -4a
1 = a so that b = 4
Wiki User
∙ 12y ago
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please help
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UndefinedImproved Answer:-The straight line equation is: y = 2x
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