Each quadrant is equals to 90°. A graph is consists of four quadrants, with each measuring 90 degrees. Quadrant I ranges from 0 degree to 90 degrees, Quadrant II is from 90° to 180°, Quadrant III is from 180° to 270°, and lastly, Quadrant IV is from 270° to 360°
I can not graph for you, but two points can be found. Zero out X and Y. -X - 3 = 0 -X = 3 X = - 3 Y = - 3, of course Draw a line from the second quadrant into the third quadrant and through the fourth quadrant connecting these two points into a descending line.
y=-x
0.75
goes through the origin, up and to the right
it lies in the 2nd and 4th quadrants
1
X = -1 The graph of this equation is a vertical line, passing through the point [ x = -1 ] on the x-axis. It's parallel to the y-axis, and extends to infinity in both directions ... up, through Quadrant II, and down, through Quadrant III.
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.
Either the answer is the point in the second quadrant, at a distance of one unit from each of the coordinate axes, or the question is incomplete.
Assuming sin equals 0.3237, the angle is in quadrant I.
depends on line slope
The value of tan and sin is positive so you must search quadrant that tan and sin value is positive. The only quadrant fill that qualification is Quadrant 1.
At what point does line represented by the equation 8x + 4y = -4 intersects the y-axis, and at what point in the negative direction of x-axis.
y=0 is a horizontal line on the x-axis. Therefore, it does not lie in any quadrant.
Each quadrant is equals to 90°. A graph is consists of four quadrants, with each measuring 90 degrees. Quadrant I ranges from 0 degree to 90 degrees, Quadrant II is from 90° to 180°, Quadrant III is from 180° to 270°, and lastly, Quadrant IV is from 270° to 360°
If A is in quadrant IV, then A/2 is in quadrant II. Yes, the fact than cos(A) is 0.1 means that A is in quadrant I or IV, but it really is not required in order to answer the question. It is superfluous.