How do you add and times 147?

Answer 1

This implies these equations:

xy = 147

x + y = 147

Solve via substitution.

y = 147/x

x + 147/x = 147

x² + 147 = 147x

x² - 147x + 147 = 0

If we graph that function and attempt to determine the zeroes of that expression, then we obtain these solutions:

x = -7/2 * (-21 + √429) and x = 7/2 * (21 + √429)

These solutions are also found by using the quadratic formula, which states that:

x = (-b ± √(b² - 4ac))/(2a) for the equation ax² + bx + c = 0 such that a is not zero.

Completing the squares also works to determine the values of x.

Finally, once you have found the x values, substitute them for either of the expressions to obtain the values for y. You should get the similar values, which are:

x = -7/2 * (-21 + √429) and y = 7/2 * (21 + √429)

x = 7/2 * (21 + √429) and y = -7/2 * (-21 + √429)