2Ca + 3O2 + 2C -> 2CaCO3
The net ionic equation for the reaction between Na2CO3 and CaCl2 to form CaCO3 is: 2Na+ + CO3^2- + Ca^2+ + 2Cl- → CaCO3(s) + 2Na+ + 2Cl-. This equation represents the ions that are involved in the reaction, excluding spectator ions.
The equation is: Ca(HCO3)2 + CaCO3 + CO2 + H2O -> 2CaCO3 + CO2 + H2O.
Carbon dioxide and water. 2HNO3(aq) + CaCO3(s) => Ca(NO3)2 (aq) + H2O + CO2
The chemical reaction between CaCO3 and 2H2O results in the formation of Ca(OH)2 (calcium hydroxide) and CO2 (carbon dioxide). The balanced equation for this reaction is: CaCO3 + 2H2O -> Ca(OH)2 + CO2.
(Don't forget to balance it) The precipitate here has to be 2NaCl, as Ca(CO3)2 technically dissolves.
The balanced chemical equation is Ca(OH)2 + Na2CO3 + 2HNO3 → Ca(NO3)2 + 2NaOH + CO2 + H2O
The complete ionic equation for the reaction is: Ca^2+(aq) + 2NO3^-(aq) + 2K+(aq) + CO3^2-(aq) --> CaCO3(s) + 2K+(aq) + 2NO3^-(aq)
The balanced equation for this reaction is: Ca(OH)2 + CO2 → CaCO3 + H2O.
The products of the reaction between Na2CO3 (sodium carbonate) and Ca(OH)2 (calcium hydroxide) are NaOH (sodium hydroxide) and CaCO3 (calcium carbonate).
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
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The aba-ca-by =2