3x3 magic square 25 total
Think! What if the magic square had an even number of cells. There's your answer.
In an 8x8 magic square, the sum of each row, column, and diagonal is the same, known as the magic constant. For an n x n magic square, the magic constant can be calculated using the formula ( M = \frac{n(n^2 + 1)}{2} ). For an 8x8 magic square, this gives ( M = \frac{8(64 + 1)}{2} = 260 ). Therefore, the sum in the 1st row of an 8x8 magic square is 260.
jack
draw it
3x3 magic square 25 total
magic
The constant is 34.
Just take any magic square, and multiply every number by 5. Here you will get another magic square with all numbers multiples of 5.
Think! What if the magic square had an even number of cells. There's your answer.
In an 8x8 magic square, the sum of each row, column, and diagonal is the same, known as the magic constant. For an n x n magic square, the magic constant can be calculated using the formula ( M = \frac{n(n^2 + 1)}{2} ). For an 8x8 magic square, this gives ( M = \frac{8(64 + 1)}{2} = 260 ). Therefore, the sum in the 1st row of an 8x8 magic square is 260.
A 1-9 magic square must add to 15.
Albrecht Dürer drew a 'magic square' in his engraving 'Melencolia I'. But I do not think he invented it.
A normal 3x3 magic square has a sum of 15. So you subtract 3 from each number in the square.
jack
No.
draw it