Think! What if the magic square had an even number of cells. There's your answer.
You can get the magic total by squaring the number, adding 1, multiplying by the number, then dividing by 2.
its impossible
harry of course
Start with a magic square which includes the number 3. Then either: Add 3 to each number, or Multiply each number by any integer other than 3.
Magic Square is arrangement of numbers within in a square of nine spaces. The number are 1-9 and each row is configured so the three numbers add up to 15.
You can get the magic total by squaring the number, adding 1, multiplying by the number, then dividing by 2.
No.
the magic sum is 15
its impossible
to help them multiplye
A simple way is to use a regular magic square and then divide each value by the same number. Dividing by a common multiple of all the number will give a magic square of fractions with all 1's as numerators
harry of course
Just take any magic square, and multiply every number by 5. Here you will get another magic square with all numbers multiples of 5.
A normal 3x3 magic square has a sum of 15. So you subtract 3 from each number in the square.
Start with a magic square which includes the number 3. Then either: Add 3 to each number, or Multiply each number by any integer other than 3.
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Magic Square is arrangement of numbers within in a square of nine spaces. The number are 1-9 and each row is configured so the three numbers add up to 15.