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Radius is from the center of a circle to the outer edge. Diameter is from the outer edge to the opposite outer edge, i.e., through the center. The diameter has twice the length of the radius.
With the information given in the question you cannot. The volume of the pipe is pi(R2 - r2)*L where R = outer radius = outer diameter*0.5 = ID/2 + thickness = 108 mm r = inner radius = inner diameter*0.5 = ID/2 = 100 mm L = length = 1000 mm Next, to convert volume to mass, you need to multiply by the density. You then need to multiply the mass by the gravitational acceleration to convert to weight. If the mass is in kilograms, and the gravitational acceleration is in metres/second2 the result will be in Newtons, the SI unit for weight.
Take out the diameter of the outer circle from the distance between the two. Gives you the diameter of the inner circle then pi r squared it.
hello stupid person! You don't know what outer diameter is...!
The Barlow formula is a simplification of Lame's formula for thin walled pipes/ cylinders. The book by AP Moser (Buried Pipe Design) gives the derivation and arrives at S = PD/2t where D is infact the average diameter. This makes sense if you consider that there is a stress profile across the pipe wall with highest stress at the inside edge. So the average stress occurs in the material at the centre (ie. Do - t). The above book has a couple of good sketches illustrating this. Outer diameter is however quoted in the Barlow equation in some contexts - for example in ASME 31.8. This is apparently a simplification (infact nominal outside diameter is used which is actually a bit smaller than the real outer diameter). If using the formula to calculate wall thickness the answer will be slightly conservative but then you will generally look up a standard wall thickness (eg. from the table in ANSI B36.10) so you will likely arrive at the same answer anyway.
Consider going across the width of the pipe: Outer diameter = Thickness + Inner diameter + Thickness so 2*Thickness = Outer diameter - Inner diameter = 2.5 - 2.1 = 0.4 inches and therefore, Thickness = 0.2 inches.
Can you calculate the ID of a pipe when you have the OD to be 10.75" and the wall thickness to be 0.5"Depends on what you know about it. If you have the outer diameter and you know the wall thickness, then ID = OD-2 x wall thickness
Weight of pipe per Meter in Kg for MS Pipes = 3.14 * (Outer diameter of pipe in Mtr. - wall thickness in Mtr. ) * Wall Thickness in Mtr. * 7850
The mass of a pipe depends on four variables: ¨ the material it is made from, ¨ its length ¨ its outer diameter ¨ the thickness of the material. The inner diameter can replace the thickness. Without information on all four it is not possible to answer the question. There is no information on the thickness of the material.
Radius is from the center of a circle to the outer edge. Diameter is from the outer edge to the opposite outer edge, i.e., through the center. The diameter has twice the length of the radius.
in the outer core it has a 6960 km.While the inner core is about 2440 km. in diameter
please i will said what i do but please make acheck if u have asteel pipe and want to know the weight of it you have to know the following 1- the outer diameter 2- the thickness of the pipe the u do the following ] (outer diam - thickness) * 3.14 * 7.85 * thikness * lenght of pipe (in millemeter) / 1000000 = the weight of the pipe * Note that : all dimension are in millimeter
Outer radius minus inner radius Subtract the inside diameter from the outside diameter, then divide the difference by 2.
For the inner area, multiply...the inner diameter x pi x the length of the pipe.For the outer area, multiply...the outer diameter x pi x the length of the pipe.
With the information given in the question you cannot. The volume of the pipe is pi(R2 - r2)*L where R = outer radius = outer diameter*0.5 = ID/2 + thickness = 108 mm r = inner radius = inner diameter*0.5 = ID/2 = 100 mm L = length = 1000 mm Next, to convert volume to mass, you need to multiply by the density. You then need to multiply the mass by the gravitational acceleration to convert to weight. If the mass is in kilograms, and the gravitational acceleration is in metres/second2 the result will be in Newtons, the SI unit for weight.
The internal diameter of the pipe times pi times its length will yield the volume it can contain. The outer diameter of the pipe times pi times its length will yield the volume that the pipe will displace when it is submerged or buried. The volume the pipe will displace minus the volume it will contain will yield the volume of material that makes up the pipe.
the outer core's thickness is 2300 km thick