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Example (assuming that you have an even sided octagon):

- height is 18" and L & W is 6 ". it's about 2 " per side of the octagon

- Area of Octagon (A) = 4.828(a*a), where a = length of each side of the octagon

Volume of Octagon = Area (A) * Height (H)

So: Volume = 4.828(a*a)*H or 4.828(2"*2")*18" = 347.6 cu in

1 gallon = 231 cu in

So: Gallons = 347.6 cu in * 1g/231 cu in = 1.5 gallons (5.7 liters)

The conversion factor for imperial gallons is 277.42 cubic inches per Imperial gallon.

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Q: How do you calculate the volume of an octagonal tank?
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