Distance alone is not enough to tell you velocity final.
(If it could, then all of the thousands of runners who finish in the same marathon
would all cross the finish line at the same speed.)
Besides distance, you would also need velocity initial, and either acceleration or time.
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
Its final velocity, the distance covered.
Acceleration = Final velocity - Initial velocity / time
No. That's only one of several possibilities. -- with initial velocity, distance, and time, you can calculate acceleration -- with final velocity, distance, and time, you can calculate acceleration -- with force and mass, you can calculate acceleration -- with initial and final momentum, you can calculate acceleration -- with initial and final kinetic energy, you can calculate acceleration -- with mass, velocity at either end, and kinetic energy at the other end, you can calculate acceleration And I'm sure there are several more that I've missed.
Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity.
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
To calculate the velocity of an object you can use the formula v=d/t. v=velocity, d=distance, and t=time. You can also calculate velocity using a=change in v/change in t, v(final)=v(initial)+at, v(average)=v(final)+v(initial)/2, or v(final)^2=v(initial)^2+2ad, or p=mv.
Final velocity = Initial velocity +(acceleration * time)
yes...
Acceleration is an object's change in velocity divided by its change in time. So: acceleration=(final velocity - initial velocity)/(final time - initial time)
change in time, initial velocity and final velocity
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t