The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle.
For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis.
If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity.
If the initial velocity is 0, the average velocity is final velocity ÷ 2.
Distance = average velocity * time.
Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis.
(final velocity ÷ 2) * time = ½ time * final velocity
...½ base * height = ½ time * final velocity
Area under graph = distance moved
Most velocity graphs are horizontal lines or sloping lines.
To calculate distance from a velocity-time graph, you would find the area under the curve, as this represents the displacement or distance traveled. If the graph is above the time axis, calculate the area above the time axis, and if it dips below, calculate the area below the time axis. Summing these two areas will give you the total distance traveled.
Two different distance-time graphs have matching velocity-time graphs when the slope of the distance-time graph represents the velocity in the velocity-time graph, as velocity is the derivative of distance with respect to time. This means that the steeper the distance-time graph, the greater the velocity on the velocity-time graph at that point.
The distance traveled can be calculated by finding the area under the velocity-time graph. The slope of the graph at any point represents the acceleration of the object. The steeper the slope, the greater the acceleration.
To go from a position graph to a velocity graph, you can calculate the slope of the position graph at each point. The slope at any given point on a position vs. time graph represents the velocity at that specific time. Therefore, the velocity graph would be a plot of the slopes at each point on the position graph.
Yes, a position-time graph can be created from a velocity-time graph by integrating the velocity values over time. By finding the area under the velocity-time curve, you can determine how the position of an object changes over time.
To find the starting point of a distance vs time graph from a velocity vs time graph and a function, you would integrate the velocity function to find the displacement function. The starting point of the distance vs time graph corresponds to the initial displacement obtained from the displaced function.
Distance covered at a given time.
Speed (in the radial direction) = slope of the graph.
distance travelled
It shows the component of velocity in a radial direction. Any motion in a transverse direction is ignored.
magnitude of acceleration (change in magnitude of velocity over time)
velocity
The variable plotted along the vertical axis is the distance in the first case, speed in the second. The gradient of (the tangent to) the distance-time graph is the speed while the area under the curve of the speed-time graph is the distance.
It is not possible to sketch anything using this browser. The speed of a body cannot be determined from a distance-time graph. The slope of the graph is a measure of the radial velocity - that is the speed directly towards or directly away from the starting point. However, there is absolutely no information of any motion in a transverse direction. Since motion in this direction cannot be assumed to be 0, the distance-time graph cannot be used to determine speed.
The position.
The velocity=distance/time ,, Suppose that the distance covered is one complete vibration therefore the distance is called wavelength and the time is called periodic time then velocity=wavelength/periodic time also frequency= 1/periodic time therefore the velocity=wavelength*frequency
Velocity = Distance/Time V = d/t
In physics, Velocity = Distance/Time. Therefore, Time= Distance/Velocity. Insert the Velocity and you get Time= Distance/100. However you'd have to convert either the distance to miles or velocity to feet. 1 mile= 5,280 feet