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Q: How do you completely factor x to the fourth power minus 4?

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It is: (x-y)4

(x2 + 1)(x2 - 2)

2x to the fourth power minus 162 equals -146

x^2(x - 4)(x + 4)

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x cubed minus 216

1x to the power of 4

3x^3(x - 4)

(3x^2 - 4y^2)(3x^2 + 4y^2)

4(10x4 + 3)(10x4 - 3)

There is a formula for the "difference of squares." In this case, the answer is (x2 - 5)(x2 + 5)

So x4 - 1 is the difference of squares, so x4 - 1 = (x2 - 1)(x2 + 1) = (x + 1)(x - 1)(x2 + 1).

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