(13x + 39)(x + 2) * * * * * Don't you think it might, instead, be (13x - 39)(x - 2)? Multiply it out, and see!
2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.
13x2=26 By Someone?
13x2
26. 13x2=26.
26
x3 + 13x2 + 42x = x(x + 6)(x + 7).
13x2 2x13
13X2
36x1 13x2 12x3 9x4 6x6
no. it can be simplified into 13x2. 13 and 2 are prime.
-x2(5x5 + 13)