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I'm guessing that's not what you really need to do.

The graph of [ y = 1/x ] is something you wouldn't recognize. It consists of two big

curved scoops that never meet anywhere on your graph. One scoop almost fills the

whole 3rd quadrant, where 'x' and 'y' are both negative, and the other one almost fills

the whole 1st quadrant, where 'x' and 'y' are both positive.

The slope of the graph at any point is [ -1/x2 ]. As you can see from that, the slope

is negative at every point on the graph, and different at every point on each scoop.

( Like any other function, you compute the slope of [ y = 1/x ] by differentiating it

with respect to 'x'.)

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Q: How do you compute the slope of the graph one over x?
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The slope of a velocity versus time graph gives acceleration. By calculating the slope of the graph at a particular point, you can determine the acceleration of an object at that specific moment in time.


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