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How do you construct a perpendicular bisector of each side of a parallelogram?
Wiki User
∙ 10y ago
With a compass and a straight edge and the lines must bisect each other at 90 degrees
Wiki User
∙ 10y ago
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How do you construct parallelogram?
With a straight edge and making sure that its length is greater than its perpendicular height and that opposite sides are parallel to each other.
what is true about the creased bisector and the line segment that is bisected?
The bisector and the line segment are perpendicular to each other.
What splits a perpendicular bisector into two congruent parts?
A perpendicular bisector splits a line segment into two congruent parts.
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
Must a bisector of a segment always be a perpendicular line?
Not always because the diagonals of a rectangle bisect each other but they are not perpendicular to each other.
How do you construct parallelogram?
With a straight edge and making sure that its length is greater than its perpendicular height and that opposite sides are parallel to each other.
what is true about the creased bisector and the line segment that is bisected?
The bisector and the line segment are perpendicular to each other.
How do you find the center of the circle?
-- Draw any two random chords of the circle. -- Construct the perpendicular bisector of each chord. -- The perpendicular bisectors intersect at the center of the circle. All of this can be done with a compass, an unmarked straight-edge, and a pencil.
What splits a perpendicular bisector into two congruent parts?
A perpendicular bisector splits a line segment into two congruent parts.
Does diagona of a parallelogram are perpendicular?
The diagonals of a parallelogram do not intersect each other at right angles and so therefore they aren't perpendicular to each other.
The apothem is a perpendicular bisector of each side of a regular polygon?
always
Is the apothem always a perpendicular bisector of each side of a polygon?
yes
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
Prove that if the diagonal of a parallelogram does not bisect the angles through the vertices to which the diagonal is drawn the parallelogram is not a rhombus?
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
Must a bisector of a segment always be a perpendicular line?
Not always because the diagonals of a rectangle bisect each other but they are not perpendicular to each other.
What kind of parellogram is it If the diagonals of a parallelogram are congruent and are perpendicular bisectors of each other?
If the diagonals are congruent and are perpendicular bisectors of each other then the parallelogram is a square. If the diagonals are not congruent but are perpendicular bisectors of each other then the figure would be a rhombus.
In a parallelogram the diagonals are perpendicular bisectors of each other What kind of parallelogram must the figure be?
It is a rhombus
