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What triangle must always have at least one angle bisector that is also a perpendicular bisector?
any isosceles triangle
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
To construct a perpendicular bisector to a given line segment one must construct two what?
Can't be sure what you're asking, but it would be two circles with equal radii longer that half the length of the segment, using the endpoints as the origins of the two circles.
Line BE is the bisector of segment AC. If AB 7 then AC .?
If line BE is the bisector of segment AC, it means that BE divides AC into two equal segments. Therefore, if AB is 7, then AC must be twice that length, making AC equal to 14.
Can a segment bisect a line?
No. Since a line is infinite, it has no mid-point. A bisector must go through a midpoint so nothing can bisect a line (not even a segment).
