Want this question answered?
x=y²
An even function is symmetric about the y-axis. The graph to the left of the y-axis can be reflected onto the graph to the right. An odd function is anti-symmetric about the origin. The graph to the left of the y-axis must be reflected in the y-axis as well as in the x-axis (either one can be done first).
True
If your graph is undirected, then its adjacency matrix will be symmetric. Faizan
A symmetric distribution.
An even function is symmetric about the y-axis. If a function is symmetric about the origin, it is odd.
Any point on the graph can be the center of a circle. If the center is on the x-axis, then the circle is symmetric with respect to the x-axis.
Odd Function
x=y²
An even function is symmetric about the y-axis. The graph to the left of the y-axis can be reflected onto the graph to the right. An odd function is anti-symmetric about the origin. The graph to the left of the y-axis must be reflected in the y-axis as well as in the x-axis (either one can be done first).
True
If your graph is undirected, then its adjacency matrix will be symmetric. Faizan
Yes!
A symmetric distribution.
f(x) = 0 is a constant function. This particular constant function is both even and odd. Requirements for an even function: f(x) = f(-x) Geometrically, the graph of an even function is symmetric with respect to the y-axis The graph of a constant function is a horizontal line and will be symmetric with respect to the y-axis. y=0 or f(x)=0 is a constant function which is symmetric with respect to the y-axis. Requirements for an odd function: -f(x) = f(-x) Geometrically, it is symmetric about the origin. While the constant function f(x)=0 is symmetric about the origin, constant function such as y=1 is not. and if we look at -f(x)=f(-x) for 1, we have -f(x)=-1 but f(-1)=1 since it is a constant function so y=1 is a constant function but not odd. So f(x)=c is odd if and only iff c=0 f(x)=0 is the only function which is both even and odd.
its true I got it right on the test
If it is a straight line through the origin then it represents a direct proportion.