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f(x) = 0 is a constant function. This particular constant function is both even and odd.
Requirements for an even function: f(x) = f(-x) Geometrically, the graph of an even function is symmetric with respect to the y-axis The graph of a constant function is a horizontal line and will be symmetric with respect to the y-axis. y=0 or f(x)=0 is a constant function which is symmetric with respect to the y-axis. Requirements for an odd function:
-f(x) = f(-x) Geometrically, it is symmetric about the origin. While the constant function f(x)=0 is symmetric about the origin, constant function such as y=1 is not. and if we look at -f(x)=f(-x) for 1, we have -f(x)=-1 but f(-1)=1 since it is a constant function so y=1 is a constant function but not odd. So f(x)=c is odd if and only iff c=0 f(x)=0 is the only function which is both even and odd.
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Is y equals 0 a continuous function?
By the definition of continuity, since the limit and f(x) both exist and are equal (to 0) at each value of x, y=0 is continuous. This is true for any constant function.
What is the solution for cosec x equals 0?
The solution for cosec x equals 0 can be found by identifying the values of x where the cosecant function equals 0. Cosecant is the reciprocal of the sine function, so cosec x = 0 when sin x = 1/0 or sin x = undefined. This occurs at multiples of π, where the sine function crosses the x-axis. Therefore, the solutions for cosec x = 0 are x = nπ, where n is an integer.
Why does sec 0 equals 1?
Secant is 1 over cosine and cosine 0 equals 1.
What is the antiderivative of zero?
The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.
What is the domain range asymptote and intercept of the equation y equals 4 times 2 exponent x?
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
