s = u + at
s = displacement
u = initial velocity
a = acceleration
t = time
rearrange to give
u = s - at
and sub in values
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
There are several definitions. not just one. Average velocity in a direction = Average displacement (distance) in that direction/time Instantaneous velocity in a direction = derivative of displacement in that direction with respect to time Average velocity in a direction = Initial velocity in that direction + Average acceleration in that direction * time Instantaneous velocity in a direction = Definite integral of acceleration in that direction with respect to time, with initial velocity at t = 0 Then there are others in which time is eliminated.
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.
the formula for finding acceleration is final velocity, minus initial velocity, all over time. So if you have the acceleration and initial speed, which is equal to the initial velocity, you must also have time in order to find the final velocity. Once you have the time, you multiply it by the acceleration. That product gives you the difference of the final velocity and initial velocity, so then you just add the initial velocity to the product to find the final velocity.
The initial acceleration of an object can be found by calculating the change in velocity over time. This can be done by dividing the final velocity by the time taken to reach that velocity. The formula for initial acceleration is: initial acceleration = (final velocity - initial velocity) / time.
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
If s = displacement, u = initial velocity, a = acceleration, t = time. Then s = ut + 1/2at2 Be careful to keep units consistent
displacement = (final velocity square + initial velocity sq. )/ 2 * acceleration
s = ut + 1/2 at^2 s=displacement u= initial velocity t=time a=acceleration
use a uniform acceleration equation, Δx = ½ (Vi + Vf) Δt where displacement = 1/2 (initial velocity + final velocity) time displacement = 1/2 (59 m/s + 78 m/s) * 12s displacement = 822 m
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t
0 km=============================You must specify the initial velocity if any acceleration was there or not.
Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity.
There are several definitions. not just one. Average velocity in a direction = Average displacement (distance) in that direction/time Instantaneous velocity in a direction = derivative of displacement in that direction with respect to time Average velocity in a direction = Initial velocity in that direction + Average acceleration in that direction * time Instantaneous velocity in a direction = Definite integral of acceleration in that direction with respect to time, with initial velocity at t = 0 Then there are others in which time is eliminated.
To find acceleration, you take Vi [Initial Velocity] and you subtract if from Vf [Final Velocity.] (Vi - Vf) If they Vi and Vf are already given, you take the two givens and you subtract them from each other. Vi minus Vf. Do not do Vf minus Vi or it will be wrong. After you do that, you divide your answer from T [Time] (Vi - Vf) a= _____ t Once you get your answer, that will be your acceleration.
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.