At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power and further reduced to 0.4 millimeters when you switch to high power. Covert the measurment for the field of view from millimeters to microns, the conventional unit of measurment in microscopy. There are 1000 microns in one millimeter.
Low power: 4mm= 4,000um
Medium power: 1.7mm= 1,700um
High power: 0.4mm= 400um
Magnification is inversely proportional to the diameter of the field of view.
to determine the radius if you only have the diameter, you divided the diameter by 2. then there you have it ! you have the radius !
low
the diameter mutliplied by pi is the circumference. From a different view the circumference divided by diameter is pi.
Yes, a calibrated ocular micrometer can be used to measure the diameter or length of a field or object. Essentially, that is all that it is used for.
Magnification is inversely proportional to the diameter of the field of view.
You can use that to estimate the size of objects that you are observing.
The answer is about 2.9mm at 80x.
Since the field of view is a circle, the size of the field of view is it's area. You would need to find the diameter of the field of view, using a transparent ruler or a micrometer. Divide the diameter measurement by 2 to get the radius. Then use the formula for the area of a circle, Area = πr2. For example, you measure the diameter of the field of view to be 2.14mm. Divide 2.14mm by 2 to get the radius, and you get 1.07mm. Square 1.07mm, which is 1.14mm2. Multiply x 3.14 (pi), and you get 3.58mm2. So the field of view for this example would be 3.58mm2.The field of view differs with different magnifications. The lower the magnification, the larger the field of view.
At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power
five
The diameter of a field is decreased by 1.5 millimeters when changed from low power to high power magnification.
0.6 mm
because the chord can be determine by the diameter and the diameter can be determine by the chord.
If the entire field of view is 32 mm and the object occupies 25% of that then you will multiply 32 by 0.25. The result is 8 mm.
to determine the radius if you only have the diameter, you divided the diameter by 2. then there you have it ! you have the radius !
Field diameter of lens B equals field diameter of lens A times total magnification of lens A divided by total magnification of lens B