there is no quadrant 0... just 1 2 3 and 4.
2-dimensional Cartesian space is naturally split into four quadrants, with one quadrant defined by x>0, y>0; one defined by x<0, y>0; one defined by x<0, y<0; and, one defined by x>0, y<0.
The point (-1,0) lies on the boundary line between Quadrants II and III .
I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
it's located on all four quadrants.
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
I would say from an educated guess that it is 0. A straight line could avoid all quadrants if it were placed on the origins of the x and y axis.
They are called "quadrants".
The coordinate or Cartesian plane is divided into four quadrants by the axes. The axes, themselves, do not belong to any quadrant. Assuming the normal x and y-axes, Quadrant I : x > 0, y > 0 Quadrant II : X < 0, y > 0 Quadrant III : X < 0, y < 0 Quadrant IV: X > 0, y < 0 That's it. No special sides, nothing to solve.
only in quadrants 2 and 3
The axes create the quadrants.
The Cartesian plane is divided into 4 quadrants
There are 4 quadrants in a circle