I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
x^2 - 15x + 56 = 0
none
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
13
(9,-2)
(8, 8)
x^2 - 15x + 56 = 0
(-8, -8)
none
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
It appears to be (8, 0) when plotted out on the Cartesian plane
13
8
(9,-2)
1/8
The point (8,0) is on an axis (abscissa axis or x-axis) and is therefore not in a quadrant.
4x-2y=16 has the solution points (0,-8) and (4, 0) at the coordinate axes, and wherever y= 4(x-4).