That will depend on the price of the tickets.
6/300
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There is not enough information in the question for us to help you !
Total cost: 9.25 times 6 = 55.50
Your question lacks the info necessary to answer it.How many tickets were sold in total?What percentage of either student or adult tickets sales were sold?Your question cannot be answered as written.
What if total of 50 raffle tickets are sold for a contest to win a car If you purchase one ticket what are your odds against winning? 49 to 1
6/300
$13230 total
7 Adult tickets 13 Child tickets
If the total is $544.50 and you bought 18 tickets, you divide the 544.50 by 18 which is $30.25 per ticket. This is only the correct answer if all of the tickets were the same price.
10 adults & 10 children's
What are they? They are what you get from the games that you play. You buy the tokens and each game takes one token. Many of the games give out tickets and when you finish collecting all the tickets they give you, you just put them into the ticket munchers, and they count/total up your tickets. You then get a receipt with the total of your tickets on it and you can redeem a prize at the merch counter depending on how many tickets you have (:
FC Barcelona, Trip Advisor, Barcelona Tourist Guide, Spain Ticket Bureau, Online Ticket Express, Total Barca, and Viagogo are all places where an individual can purchase season tickets to Barcelona FC.
90 tickets were sold for a concert x tickets were sold for 3 dollars and the rest were sold for 4 dollars the total amount for the 90 tickets that were sold is 300 how many ticket were sold for x?
Let's assume the cost of a child's ticket is x. Then, the cost of an adult's ticket would be 2x. The total cost of two adults' tickets and three children's tickets is 2(2x) + 3(x) = 4x + 3x = 7x. We know that 7x = 28, so x = 4. Therefore, the cost of a child's ticket is $4, and the cost of an adult's ticket is $8.
It would be $160
Sounds like a system of equations. X = adult ticket Y = student ticket Change all to pennies for convenience. X + Y = 105 300X + 150Y = 25000 -150(X + Y = 105) - 150X - 150Y = - 15750 300X + 150Y = 25000 -----------------------------------add them 150X = 9250 X = 62 adult tickets ------------------------ Y = 43 student tickets -------------------------- Those two prices added together = $250.50 So, we are a little off. I rounded the adult ticket number, but pieces of tickets can not be sold, so check work.