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I'll try to explain it.

We know that an adult's ticket is two times the cost of a child's ticket. We will call the child's ticket "y". If we do so, the adult's ticket will be 2"y" because it's two times the cost of a child's ticket. We also know that the total cost is 28. Now, we'll write an equation, knowing the number of children and adults and the relationship between the costs:

2*2y will be the two adult's tickets.

3*y will be the three children's tickets.

The equation:

2*2y+3*y=28

4y+3y=28

7y=28

y=4

Now, we know that ONE child's ticket costs 4. To find out how much an adult's ticket costs, we have to double it (look at the exercise, it says that an adult's ticket is two times the cost of a child's ticket).

4*2=8

Finally, we've found out that a child's ticket costs 4 and an adult's ticket costs 8.

We can check it as well:

2*8+3*4=16+12=28

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