3(2x-4)=2(4x+3)
Does a multi-step equation sometimes, always, or never have a solution?
2x3x2
well, an equation with one variable is a one step equation and an equation with more than 2 variables is a multi-step equation
2x+2=12
3(2x-4)=2(4x+3)
It is 12=12/4-7=9
A multi-step equation that equals 27 could be (3x + 9 = 27). To solve for (x), first subtract 9 from both sides to get (3x = 18), and then divide by 3 to find (x = 6).
17
One example of a multi-step equation that equals 23 is (2x + 5 = 23). To solve for (x), first subtract 5 from both sides, resulting in (2x = 18). Then, divide both sides by 2 to find (x = 9). Therefore, the equation satisfies the condition of equaling 23 when solved.
A multi-step equation that equals 10 could be (3x + 4 = 10). To solve for (x), you would first subtract 4 from both sides, resulting in (3x = 6). Then, divide both sides by 3, giving (x = 2). Thus, the equation (3(2) + 4 = 10) confirms that it equals 10.
One-step equation 3x=12 x-6=5 4/x=7 Multistep equation 3x+8=11 x/7+4=6 4x/7=2
2n+4=66