Does a multi-step equation sometimes, always, or never have a solution?
Chat with our AI personalities
No. Sometimes they are both extraneous.
None.Whatever number you substitute for 'x', 0x will always be 0,and the equation will always become [ 0 = 4 ].No value of 'x' can make [ 0 = 4 ]. There is no solution.
In math, an equation that is always true is called an identity.
In the graph of a quadratic equation, the plotted points form a parabola. This parabola usually intersects the X axis at two different points. Those two points are also the two solutions for the quadratic equation. Alternatively: Quadratic equations are formed by multiplying two linear equations together. Each of the linear equations has one solution - multiplying two together means that the solution for either is also a solution for the quadratic equation - hence you get two possible solutions for the quadratic unless both linear equations have exactly the same solution. Example: Two linear equations : x - a = 0 x - b = 0 Multiplied together: (x - a) ( x - b ) = 0 Either a or b is a solution to this quadratic equation. Hence most often you have two solutions but never more than two and always at least one solution.
A linear equation in one variable. Case 1: A conditional equation: True only for a value of the variable. Ex. x + 2 = 3, True only when x is 1. Case 2: Identity Equation: Always true. Ex. x + 2 = x + 2, True for any value of x. Case 3: x + 1 = x + 5, False for any value of x. We call a solution any value of the variable that satisfies the equation, meaning if we replace the variable with that value, the equation becomes a true statement. Example: -2(x -3) = 8 - 2x -2x + 6 = 8 - 2x (add 2x and subtract 6 to both sides) 0 = 2 False. Since this equation, which is equivalent to the original equation, is false, then the original equation is also false. Meaning, there is no real number for x that could satisfy the equation. So there is no solution to the equation.