Rectangles don't have volume, they have area. Only 3 dimensional figures have volume.
There are many possible answers. You could draw a 4 cm x 7 cm rectangle and remove a 1 cm x 3 cm rectangle from it.
Draw two long parallel lines, both 4 cm, 2 cm apart, then draw the other two lines of the rectangle. You can measure the perimeter if you want. It's exactly 12 cm.
The answer is 12 cm.
To draw a rectangle that's 20 by 15 meters on a A4 piece of paper you could add a scale perhaps for every 1 cm drawn on the paper would be 5 meters in reality. Doing this would allow you do simply draw a 4 by 3 cm rectangle. You could however change the scale suit yourself.
The area of rectangle is : 24.0
Base of rectangle: 24/6 = 4 cm
When a rectangle measuring 8 cm by 3 cm is dilated by a scale factor of 4, each dimension is multiplied by 4. This means the new length will be 8 cm × 4 = 32 cm, and the new width will be 3 cm × 4 = 12 cm. Consequently, the dilated rectangle will have dimensions of 32 cm by 12 cm.
Length of rectangle: 7.9 cm Width of rectangle: 1.3 cm Area of rectangle: 7.9 times 1.3 = 10.27 square cm
To draw a rectangle with an area of 24 cm² and a perimeter of 28 cm, we need to find the dimensions that satisfy both conditions. Let the length be ( l ) and the width be ( w ). The area equation is ( l \times w = 24 ) and the perimeter equation is ( 2(l + w) = 28 ). From the perimeter, we get ( l + w = 14 ). Solving these two equations simultaneously, we can express ( w ) as ( w = 14 - l ) and substitute it into the area equation to find ( l ) and ( w ) are 6 cm and 4 cm, respectively. Thus, the rectangle can be drawn with dimensions 6 cm by 4 cm.
Draw a 10 x 20 rectangle.
width = (x + 4) cm length = [(x + 4) + (x + 7)] cm Rectangle Perimeter = 2[(x + 4) + (x + 4 + x + 7)] cm Rectangle Perimeter = 2[(x + x + x) + (4 + 4 + 7)] cm Rectangle Perimeter = 2(3x + 15) cm Rectangle Perimeter = (6x + 30) cm
The area of rectangle is : 28.0