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How do you draw a shape with a length of 4 cm width of 7 cm and the area of 25 sq cm?
There are many possible answers. You could draw a 4 cm x 7 cm rectangle and remove a 1 cm x 3 cm rectangle from it.
How do you draw special rectangles that have perimeters of 12 centimeters?
Draw two long parallel lines, both 4 cm, 2 cm apart, then draw the other two lines of the rectangle. You can measure the perimeter if you want. It's exactly 12 cm.
What is the perimeter of 4 centimeters by 2 centimeters rectangle?
The answer is 12 cm.
Need to draw a rectangle that is 20 meters by 15 meters?
To draw a rectangle that's 20 by 15 meters on a A4 piece of paper you could add a scale perhaps for every 1 cm drawn on the paper would be 5 meters in reality. Doing this would allow you do simply draw a 4 by 3 cm rectangle. You could however change the scale suit yourself.
What is the area of a rectangle that is 6 cm long and 4 cm wide?
The area of rectangle is : 24.0
What is the base of a rectangle has an area of 24 cm and a height of 6 cm.?
Base of rectangle: 24/6 = 4 cm
The length of a rectangle is 4 more than 3 times the width. if the perimeter of the rectangle is 18.4 cm what is the area of the rectangle?
Length of rectangle: 7.9 cm Width of rectangle: 1.3 cm Area of rectangle: 7.9 times 1.3 = 10.27 square cm
Rectangle A is width 4 and length 8 so draw similar rectangle scale factor 2.5?
Draw a 10 x 20 rectangle.
How do you draw a rectangle with area 24 cm2 and perimeter 28 cm?
To draw a rectangle with an area of 24 cm² and a perimeter of 28 cm, we need to find the dimensions that satisfy both conditions. Let the length be ( l ) and the width be ( w ). The area equation is ( l \times w = 24 ) and the perimeter equation is ( 2(l + w) = 28 ). From the perimeter, we get ( l + w = 14 ). Solving these two equations simultaneously, we can express ( w ) as ( w = 14 - l ) and substitute it into the area equation to find ( l ) and ( w ) are 6 cm and 4 cm, respectively. Thus, the rectangle can be drawn with dimensions 6 cm by 4 cm.
The width of a rectangle is X plus 4Cm its length is X plus 7Cm greater than its width represent its perimeter and simplify?
width = (x + 4) cm length = [(x + 4) + (x + 7)] cm Rectangle Perimeter = 2[(x + 4) + (x + 4 + x + 7)] cm Rectangle Perimeter = 2[(x + x + x) + (4 + 4 + 7)] cm Rectangle Perimeter = 2(3x + 15) cm Rectangle Perimeter = (6x + 30) cm
What is the area of a rectangle that has a width of 7 cm and a length of 4 cm?
The area of rectangle is : 28.0
Draw a shape that has a perimeter of 12 and an area of 6 sq cm?
A rectangle with dimensions 3 cm by 2 cm would meet the criteria. The perimeter is calculated as (2(length + width) = 2(3 + 2) = 10) cm, which does not satisfy the requirement. However, a rectangle with dimensions 4 cm by 1 cm has a perimeter of 10 cm and an area of 4 sq cm. A shape like a triangle with a perimeter of 12 cm and an area of 6 sq cm could be a right triangle with sides of 3 cm, 4 cm, and 5 cm.
