How do you draw a rectangle with area 24 cm2 and perimeter 28 cm?

Answer 1

To draw a rectangle with an area of 24 cm² and a perimeter of 28 cm, you first need to determine the dimensions. Let the length be ( l ) and the width be ( w ). From the area, you have the equation ( l \times w = 24 ), and from the perimeter, ( 2l + 2w = 28 ) simplifies to ( l + w = 14 ). Solving these equations, you find the dimensions to be ( l = 12 ) cm and ( w = 2 ) cm or vice versa, allowing you to draw the rectangle accordingly.

Answer 2

To draw a rectangle with an area of 24 cm² and a perimeter of 28 cm, we need to find the dimensions that satisfy both conditions. Let the length be ( l ) and the width be ( w ). The area equation is ( l \times w = 24 ) and the perimeter equation is ( 2(l + w) = 28 ). From the perimeter, we get ( l + w = 14 ). Solving these two equations simultaneously, we can express ( w ) as ( w = 14 - l ) and substitute it into the area equation to find ( l ) and ( w ) are 6 cm and 4 cm, respectively. Thus, the rectangle can be drawn with dimensions 6 cm by 4 cm.