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(CD - ab)^2 = (CD - ab)(CD - ab)

= c^2 d^2 - 2abcd + a^2b^2

Try it with say a = 4, b = 3, c = 2 & d = 1:

Then CD = 2 and ab = 12 so CD - ab = -10 and squared = 100

c^2 = 4

d^2 = 1 so c^2d^2 = 4 x 1 = 4

a^2 = 16

b^2 = 9 so a^2b^2 = 16 x 9 =144

2abcd = 48

giving 4 - 48 + 144 = 100. Shazam!

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Q: How do you expand cd-ab if the entire expression is in parentheses and squared?
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