-132
Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
The area of the whole circle is PI x 6 squared which equals 36 PI. We can now use the ratio 30/36 = x/360 to find the angle (360 is the full angle if the circle, x is the angle of the segment, pi's cancell out) If we solve for x we get 300 degrees which is the angle we need. As for the length, the circles circumference is 12 PI (12 is the diameter). This means that 30/36= AB/12PI AB=10PI
100cm squared = 0.01 metres squared
If these are vectors, then ba = - ab
ab(ab) =2ab
A^2-2ab+B^2 is actually (A+B)^2 AB squared is A^2B^2 or (AB)^2
b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.
(a+b)(a squared-ab+b squared)
The length of its side squared.
ab x ac = ab - ac
(a + x^2)(b + y^2)
-132
-2a^2
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
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