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(a-b)^2 doesn't have a numeric value since there are no numbers associated with it, but you can definitely expand it, as it represents a formula, instead of an actual numeric expression.

(a-b)(a-b)

= a^2-ab-ab+b^2

= a^2-2ab+b^2 (which is actually the rule for expanding!)

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Q: What is A-B squared?
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Related questions

What is A B squared?

A^2-2ab+B^2 is actually (A+B)^2 AB squared is A^2B^2 or (AB)^2


What is b squared plus ab minus two minus two b squared plus two ab?

b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.


Is ab squared the same as 2ab?

No, ab squared is not the same as 2ab. ab squared (ab^2) means multiplying ab by itself, resulting in a^2 * b^2. On the other hand, 2ab means multiplying 2 by a and then by b, resulting in 2ab. These two expressions are not equivalent because ab^2 involves squaring the variable b, while 2ab does not involve squaring any variables.


What is the area of square AB?

The length of its side squared.


A B and C are all squared numbers. A b also a c and b c make squared numbers what are A B and c?

ab x ac = ab - ac


Factor x squared y squared plus ay squared plus ab plus bx squared?

(a + x^2)(b + y^2)


What does this equal to 12a squared b squared - 144ab?

-132


What is the answer when Ab is not equal to 0 -12a cubed times b squared over 6ab squared?

-2a^2


Factor X squared y plus axy plus abx plus a squared b?

x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)


Why does b times ab equal ab squared and not equal ab plus b squared?

b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2


Factor ab - 2ac plus b squared - 2bc?

4


Factor x squared y - xyb - abx plus ab squared?

Factor by grouping. x2y - xyb - abx + ab2 The first two can factor out an xy, so xy(x - b) The second two can factor out a -ab, so -ab(x - b) and we have xy(x - b) - ab(x - b) Since what is inside the parentheses is alike, we can be assured that we have factored correctly and now continue to group: ANS: (x - b)(xy - ab)