8
15 x 2 = 30
95
Here is one factor tree of 300: 300 20 x 15 (4x5) x (3x5) ((2x2)x5) x (3x5) You have reduced it to prime numbers, so you are finished. The factors of 300 are 2, 2, 3, 5, and 5.
Multiply the factors, and you will know.
The GCF is x5
math
1080 = 2^3x3^3x5 200= 2^3x5^2 LCM (1080,200) = 2^3x3^3x5^2 = 1800
3a + a = 4a Example: a = 5 (3x5) + 5 = 15 + 5 = 20 = 4 x 5
There are 15 cells in a 3x5 table, calculated by multiplying the number of rows (3) by the number of columns (5).
No it can't !!!Matrix property: A matrix A of dimension [nxm] can be multiplied by another B of dimension [ txs] m=t.m=t => there exist a C = A.B of dimension [nxs].Observe that given [3x5] and [3x5], 5!=3(not equal to) so you can't!
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
x2(x-4)