Q: What number has the this prime factorzation 2 the 4 power x 3x5?

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3 and 5 are Prime Factors of 15 (3x5=15).

Prime factor each number. Use each prime factor the most it was used in any one number. 15=3x5 25=5x5 30=2x3x5 2x3x5x5=150

composite cuz 2x5=10 then 3x5=15 and it goes on

The LCM of the given numbers is the product of all different prime factors to their greatest power. If there are no exponents, the greatest power of the prime factors is 1 and each different prime factor is used in the multiplication:prime factors of 15 are 3 x 5;prime factors of 21 are 3 x 7;the LCM of 15 and 21 is 3 x 5 x 7 = 105

All of them. 1x15,2x7.5, 3x5, 4x3.75, 5x3...

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3 and 5 are Prime Factors of 15 (3x5=15).

3x5

4 = 4, and 4 = 2 x 2, so either a single prime number to the power 4-1 (23, 33, etc.), or two different prime numbers, each to the power 2-1, for example, 2x3, 2x5, 3x5, etc.

There are 15 cells in a 3x5 table, calculated by multiplying the number of rows (3) by the number of columns (5).

Prime factor each number. Use each prime factor the most it was used in any one number. 15=3x5 25=5x5 30=2x3x5 2x3x5x5=150

composite cuz 2x5=10 then 3x5=15 and it goes on

6 is 2x3 and 15 is 3x5 just basic facts no exponents

The LCM of the given numbers is the product of all different prime factors to their greatest power. If there are no exponents, the greatest power of the prime factors is 1 and each different prime factor is used in the multiplication:prime factors of 15 are 3 x 5;prime factors of 21 are 3 x 7;the LCM of 15 and 21 is 3 x 5 x 7 = 105

To find this you first have to identify the prime factors of each number. In this case they are: 15 = 3x5 51 = 3x17 The next step is to identify any common prime factors. In this case both numbers have a 3 as a prime factor. Therefore the HCF of 15 and 51 is 3.

13 is prime 14=2x7, 2 factors 15=3x5, 2 factors 16=24, 4 factors 17 is prime 18=2x32, 3 factors 19 is prime So the answer is 3 (14, 15 and 16)

All of them. 1x15,2x7.5, 3x5, 4x3.75, 5x3...

3x5+4=19