Q: How do you factor 216X to the sixth power minus 125x to the sixth power?

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(5x - 2)(25x2 + 10x + 4)

(5x + y)(25x^2 - 5xy + y^2)

√125X² = 125X

3x + 2x - 8 = 125x - 8 = 125x = 20x = 4

The answer is 84128.

125x squared

Power Factor is one of most significant parameter in calculating AC Power. As we know it is cosine of angle between AC Voltage and Current it comes in picture while calculating power in AC circuits Power In AC (P) = Voltage (V) X Current (V) X Power Factor Let us take an example of Power with Power factor and without power factor for same circuit. Let Us assume V = 125 Volts I = 1 Amp Power Factor = 1 Then P = 125X1X1= 125 Watts But for any circuit when Power factor is below 1, to execute same power, Circuit has to draw more current. for example P = 125X 1.25 X 0.8 = 125 Watts In first example power factor of the circuit was unity = 1 and in that condition current of the circuit was 1 amp whereas in second example power factor of the circuit is 0.8 due to which current of the circuit increases to 1.25 amp to execute the same power. Now due to increase in current of the circuit many factors are affected like heat loss, Conductor's specification , Class of insulation etc. Thus it can be concluded after going through above explanation that power factor play a significant role in AC power calculation as well as in actual practices.

5 + 7 = 125x -3x = 2x

5x^3 + 15 x^2 - 125x - 375 = 5(x^3 + 3 x^2 - 25x - 75) = 5[(x^3 + 3 x^2) - (25x + 75)] = 5[x^2(x + 3) - 25(x + 3)] = 5[(x + 3)(x^2 - 25)] = 5(x + 3)(x + 5)(x -5)

125x * 0.16 = 20x = 20 / 0.16x = 125

27/5 = x/125x = 324x = 64.864.8 twelfths

5x-8 = x+125x-x = 8+124x = 20x=5