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The expression cannot be factorised.
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2x2 plus 42 equals x2 plus 13x?
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
42 plus X squared equals 13X?
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}
What binomial is the factor of x2-13x 42?
(x - 6)(x - 7)
What binomial is a factor of this trinomial x2 plus 13x plus 4?
x2 + 13x + 4 = (x + 6½ + √38¼)(x + 6½ - √38¼). To find this, we need to find p and q, where p + q = 13, pq = 4. 4 = 42¼ - 38¼ = (6½ + √38¼)(6½ - √38¼); thus, p = (6½ + √38¼), q = (6½ - √38¼).
What is the factorization of this trinomial x3 plus 13x2 plus 42x?
x3 + 13x2 + 42x = x(x2 + 13x + 42) = x(x2 + 6x + 7x + 42) = x[x(x + 6) + 7(x + 6)] = x(x + 7)(x + 6)
2x2 plus 42 equals x2 plus 13x?
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
Which of the binomials below is a factor of this trinomial x2 - 13x plus 42?
(x - 6)(x - 7)
42 plus X squared equals 13X?
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}
If x2 - 13x plus 42 equals x plus Ax plus B then A plus B equals?
2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
What binomial is the factor of x2-13x 42?
(x - 6)(x - 7)
Factorise x squared plus 13x plus 42?
It is (x+6)(x+7) when factored
How do you factor -2x2 5x 42?
-((2x + 7)(x - 6))
How do you factor xsquared-13x plus 42?
In order to factor this expression we are going to write it as 2 expressions (factors) which when multiplied together equal x2 - 13x + 42.We can see straight away that the simplest way to end up with x2 is to have an "x" in each factor.This then just leaves us to find two numbers which when added together result in -13 and when multiplied result in 42.It likely will not take you too long to see that -6 & -7 would do this.Thus we can factor this to:(x-6) (x-7)
What binomial is a factor of this trinomial x2 plus 13x plus 4?
x2 + 13x + 4 = (x + 6½ + √38¼)(x + 6½ - √38¼). To find this, we need to find p and q, where p + q = 13, pq = 4. 4 = 42¼ - 38¼ = (6½ + √38¼)(6½ - √38¼); thus, p = (6½ + √38¼), q = (6½ - √38¼).
Which of the binomials below is a factor of this trinomial x2-13x 42?
Hopefully, one of the binomials below is either (x - 7) or (x - 6)
Factor 6x plus 42?
6(x + 7)
What is the factor of this trinomial x2 plus 13x plus 42?
The easiest way to factor x2 + 13x + 42 is to look at the last number. The last number is 42. Now, think of what whole numbers you can multiply to equal 42. 1 x 42 2 x 21 3 x 14 6 x 7 If you look at the equation, we notice that the sign pattern is + + + When the sign pattern is + + +, we know that whatever two factors you choose must add up to the middle number, 13. So, automatically we can get rid of some of these factors. 1 x 42 --> 1 + 42 doesn't equal 13 2 x 21 --> 2 + 21 doesn't equal 13 3 x 14 --> 3 + 14 doesn't equal 13 Now, we're automatically left with 6 x 7. So, your answer would be (factored out), (x+6)(x+7) Where x = -7, -6
