2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)
(2x - 7)(x + 1)
8 times(2x2 - 5x - 3) = 8(2x + 1)(x - 3)
3x2 - 5x2 = -2x2
2x3 - 5x2 + 5x - 2 = x(2x2-5x+3) + 2x - 2 = x(2x-3)(x-1) + 2(x-1) = (x-1)[x(2x-3)+2] = (x-1)(2x2-3x+2) I did it by trial and error, through experience -- no set procedure. (2x2-3x+2) cannot be factored, which is evidenced by calculating (b2-4ac), where a = 2; b=-3; and c=2 from the expression (2x2-3x+2). (b2-4ac) = (9-16) = -7, which has no real square root value. That is, sqrt(-7) is an imaginary number. ========================
2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)
2X2+5x-12 4+5x-12 -8+5x 5x-8
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
Show the terms as additive here..., 8X2 + 10X3 factor out 2X2 2X2(4 + 5X) ---------------- 2X2 ==== greatest common factor
(x + 1)(2x - 7)
(x - 2)(2x + 9)
The expression cannot be factorised.
You would first factor out anything that is common between the 3 parts. 2x2 is the greatest common factor. To pull out the 2x2, you divide each term by 2x2 like so:12x4/2x2=6x210x3/2x2=5x-12x2/2x2=-6We now know that 12x4+10x3-12x2= 2x2(6x2+5x-6)The next step involves using the "slip and slide" method for the trinomial inside the parentheses:6x2+5x-6x2+5x-36(x+9)(x-4)(x+9/6)(x-4/6)(x+3/2)(x-2/3)(2x+3)(3x-2)Remembering that the result for the slip and slide method only accounts for 6x2+5x-6 we must multiply (2x+3)(3x-2) by 2x2.Your final answer is 2x2(2x+3)(3x-2).
2x2 + 5x - 3 (2x - 1)(x + 3)
2x2-2 = -5x-1 2x2+5x-2+1 = 0 2x2+5x-1 = 0 Use the quadratic equation formula to find the values of x: x = 0.1861406616 or x = -2.686140662
7x(3x3 - 2x2 + 5x + 1)
ex: 2x2 + 6bx + 5x + 15b Group 1st 2 terms and last 2 terms. Factor separately. = (2x2 + 6bx) + (5x + 15b) Factor using gcf = 2x(x + 3b) + 5(x + 3b) notice the parenthesis are the same = (2x + 5)(x + 3b)