-((2x + 7)(x - 6))
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2x2 - 5x + 12 does not factor. 2x2 - 5x - 12 factors into (2x + 3)(x - 4) 2x2 + 5x - 12 factors into (2x - 3)(x + 4)
(2x - 7)(x + 1)
8 times(2x2 - 5x - 3) = 8(2x + 1)(x - 3)
3x2 - 5x2 = -2x2
2x3 - 5x2 + 5x - 2 = x(2x2-5x+3) + 2x - 2 = x(2x-3)(x-1) + 2(x-1) = (x-1)[x(2x-3)+2] = (x-1)(2x2-3x+2) I did it by trial and error, through experience -- no set procedure. (2x2-3x+2) cannot be factored, which is evidenced by calculating (b2-4ac), where a = 2; b=-3; and c=2 from the expression (2x2-3x+2). (b2-4ac) = (9-16) = -7, which has no real square root value. That is, sqrt(-7) is an imaginary number. ========================