Divide all terms by 4 and it then factors as: (v+4)(v-12)
The answer is -4v + 83v^2.
Step 1. Divide by 4v: 4v(3v2 + v - 24) Step 2. 4v(3v - 8)(v + 3)
(3g + 4v)(9g2 - 12gv + 16v2)
24uv + 35u2 - 30u3 - 28v = 24uv - 28v - 30u3 + 35u2 = 4v*(6u - 7) - 5u2(6u - 7) = (4v - 5u2)*(6u - 7)
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Yes I can. = v-16-4v = -4v-2 = you have to move all the variables to one side, and all the numbers to the other side... v - 4v + 4v = 16 -2 v= 14
-20v + 4v2 - 5y + vy = 4v2 - 20v + vy - 5y = 4v*(v - 5) + y*(v - 5) = (4v + y)*(v - 5)
it equals 3+4v
It is equal to: 20v^2 +4v -24
Solve S = 4v2 for v . -4(4-v)= -2(2v-1) v-16+4v = -2(2v-1) v-16+4v = -4v + 2 -16+5v = -4v + 2 5v = -4v + 18 9v = 18 v = 2
-8-3v = 4v+48 -3v-4v = 48+8 -7v = 56 v = -8
In older cars 4v = a four barrel carburetor. 2v would be a two barrel and a 1v would be one barrel