4X^2 + 27X + 35 = 0
Quadratically. The discriminant says..........
27^2 - 4(4)(35) = 169 > 1, so 2 real roots, though they may be ugly.
X = -b +/- sqrt(b^2-4ac)/2a
a = 4
b = 27
c = 35
X = -27 +/- sqrt[27^2 - 4(4)(35)]/2(4)
X = -27 +/- sqrt(169)/8
X = [-27 +/- 13]/8
X = - 7/4
X = -5
My TI-84 graphing calculator confirms this answer
To factor: 10x2 + 27x - 28 Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor: = 10x2 + 35x - 8x - 28 = 5x(2x + 7) - 4(2x + 7) = (5x - 4)(2x + 7)
35 - 4 × 2 = 35 - (4 × 2) = 35 - 8 = 27
You need to know whether the given factor is x + 5 or x - 5. Then it is a simple problem in long division.
(x - 5)(5x - 7)
(x + 7)(x - 5)
280
x2-12x+35 = (x-5)(x-7)
(3x - 5)(2x + 7)
7 is a factor of 35.
The answer is 350. Simply add the numbers together like you would for two plus two. To check your work, a calculator is the best option.110
35
(z - 6)(z - 6)