To factor:
10x2 + 27x - 28
Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor:
= 10x2 + 35x - 8x - 28
= 5x(2x + 7) - 4(2x + 7)
= (5x - 4)(2x + 7)
(5x - 4)(2x + 7)
5 + (10 x 2) + 8 ÷ 4 + 1 = 28
6x2=12 2x-28=?
Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913
(4)(2)+7x-28+7x-27x-6.This expression cannot be simplified further nor solved (because it is not equal to anything).
(5x - 4)(2x + 7)
5 + (10 x 2) + 8 ÷ 4 + 1 = 28
-2x+12x+28=10x+28 ;Combining like factors2(5x+14) ; Factor out a two from both of them
6x2=12 2x-28=?
Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913
7(x + 4)
(4)(2)+7x-28+7x-27x-6.This expression cannot be simplified further nor solved (because it is not equal to anything).
7(y + 4)
It is 7*(12 + 4).
-28
4(7 + 5)
-28