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To factor:
10x2 + 27x - 28
Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor:
= 10x2 + 35x - 8x - 28
= 5x(2x + 7) - 4(2x + 7)
= (5x - 4)(2x + 7)
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10x2 plus 27x - 28?
(5x - 4)(2x + 7)
5 plus (10x2) plus 8 divide 4 plus 1?
5 + (10 x 2) + 8 ÷ 4 + 1 = 28
How do you factor 6x2 plus 2x-28?
6x2=12 2x-28=?
What are the zeros or x-interecepts or soultions or roots of the quadratic equation -7x2 - 27x plus 28 equals 0?
Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913
What is 4 times 2 plus 7x - 2?
(4)(2)+7x-28+7x-27x-6.This expression cannot be simplified further nor solved (because it is not equal to anything).
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