8x2-10x-3 = (2x-3)(4x+1) when factored
(2y - 5)(y - 2)
15.
Factor it. (x - 8)(x - 2) x = 2, 8
68.3
Three of anything minus ten of the same thing leaves negative seven of them.
Ten minus four point three five equals five point six five.
6 and 5/8.
It is seven and three fourths.
Times ten, minus three, times ten, minus three
Negative three.
10 - -3 = 13
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .