0
x^(2) - 10x + 16 = 0
Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'.
Setting up brackets
( x 2)(x 8)
Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative.
Hence
(x - 2)(x - 8 ) = 0
When
x - 2 = 0 x = 2
& when
x - 8 = 0
x = 8
So the two answers are ,2, & ,8, .
What else can I help you with?
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