8X^2 - 4X^2
factor out a 4X^2
4X^2(4 - 1)
all I can see to do
4X^2 - 8X factor out 4X 4X(X - 2)
(2x - 1)(4x + 1)
(4x - 3)(2x + 3)
(2x - 1)(2x + 5)
(4x-8)(2x+2)
(z - 8x)(z + 8x)
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
8x2 -18x+9=(2x+-3)(4x+-3)
(8x - 3)(8x + 3)
2(4x - 3)
(x-3)(3x+1)
There is a formula for the "difference of squares." In this case, the answer is (8x + 5y)(8x - 5y)