How do you factor 4x squared minus 8x?

Answer 1

4x^(2) - 8x

'4' is common to both '4' & '8' . So tak outr '4'.

Hence

4(x^(2) - 2x)

Inside the brackets 'x' is common to both 'x^(2) & '2x'. So take out 'x'.

Hence

4x(x - 2)

Done , fully factored.

Answer 2

4X^2 - 8X

factor out 4X

4X(X - 2)

Answer 3

8X^2 - 4X^2

factor out a 4X^2

4X^2(4 - 1)

all I can see to do