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4x^(2) - 8x

'4' is common to both '4' & '8' . So tak outr '4'.

Hence

4(x^(2) - 2x)

Inside the brackets 'x' is common to both 'x^(2) & '2x'. So take out 'x'.

Hence

4x(x - 2)

Done , fully factored.

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lenpollock

Lvl 16
1mo ago
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Wiki User

13y ago

4X^2 - 8X

factor out 4X

4X(X - 2)

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Wiki User

13y ago

8X^2 - 4X^2

factor out a 4X^2

4X^2(4 - 1)

all I can see to do

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Q: How do you factor 4x squared minus 8x?
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