x2 - 8x = x*x - 8*x = x*(x - 8)
5 - 8x + 3x2 = 3x2 - 8x + 5 (since the sign of the second term is negative, then 5 can be factored as (-1)(-5)) = (3x - )(x - ) (try to put 1 or 5 to the empty places, in order to obtain -8x) = (3x - 5)(x - 1)
(x + 1)(x - 8)
(x - 2)(2x + 3)
The factoring is as follows: x2 - y2 = (x + y) * (x - y)
x^2 - y^2 - 4 is in its simplest form.
(8x - 3)(8x + 3)
(x-3)(3x+1)
(x - 5)(x - 3)
What about it? Factorise it?
x^(2) - 8x + 12 Write down all the pairs of factors of '12'. They are ( 1,12) , ( 2, 6) , ( 3 ,4). Select a pair that add to '8' . Viz, ( 2,6). Set up brackets ( x 6)(x 2) Which signs???? Since '12' is positive (+), then both the signs are the same. Since '8' is negative(-), then both signs are negative. Hence ( x - 6)(x - 2) Fully factored . Done!!!!!!
x - 3
x - 5
3x2 - 8x = x(3x - 8)
x2-9x+8=0 has two solutions:x = 8x = 1
x=3
x^2 +8x -9 is equivalent to (x+9)(x-1) when factored
If: x^2 -8x = -12 then x^2-8x+12 = 0 and so x = 2 or x = 6