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Let the symbol ^ mean "to the power"

Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2

Q: How do you factor 9x squared plus 24x plus 16?

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(3x + 4)(3x + 4)

16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16

(b + 4)(b + 4)

2(x + 4)(x + 2)

x^2 + 10x + 16 = (x + 8)(x + 2)

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(3x + 4)(3x + 4)

(24x)^5 - (24x)^3 + (16x)^2 - 16 This can be simplified multiple ways: 1. pull (24x)^3 out of the first two terms and 16 out of the second two. (24x)^3((24x)^2-1) + 16(16x^2-1) 2. just pull 8 out of everything 8(3*(24x)^4-3*(24x)^2+32x^2-2) ...

16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16

(b + 4)(b + 4)

2(x + 4)(x + 2)

x^2 + 10x + 16 = (x + 8)(x + 2)

(3x - 2)(x + 8)

(5r - 4)(5r + 4)

Presumably you mean: 9x2+24x+16? (3x+4)(3x+4)

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

2(x - 2)(x - 4)

9x squared plus 16 = 0 factored is plus and minus 4/3 i.