2(x - 2)(x - 4)
(x-3)(x-9) = 0
(3x - y+ 2)(3x + y + 2)
30+12x = 6(5+2x)
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
6(x + 1)(x + 1)
(x-3)(x-9) = 0
(3x - y+ 2)(3x + y + 2)
30+12x = 6(5+2x)
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
6(x + 1)(x + 1)
2(x + 4)(x + 2)
(2x - 1)(6x + 5)
(2x - 3)(2x - 3)
(x - 8)(x - 4)
(-3, -5)
The answer is (2x^2+3)(4x+1)
Re=Write as 16x^(3) + 12x^(2) + 4x Take out the common factor of '4' Hence 4(4x^(3) + 3x^)2) + x) Take out the common factor of 'x' Hence 4x( 4x^(2) + 3x + 1) The answer!!!!!