3x^(2) - 24x + 48
Factor out '3'
3(x^(2) - 8x + 16)
3(x - 4)(x - 4)
Fullt factored.
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
3x2-24x-48 is not factorable.
3x2 + 27x +60
The idea is to solve the equation -3x2 + 24x - 19 = 0. You can use the quadratic formula for this, using a = -3, b = 24, c = 19. Or complete the square since dividing by -3 will give us 8x, an even coefficient. -3x2 + 24x - 19 = 0 (add and subtract 48 to the left side) -3x2 + 24x -48 + 29 = 0 (subtract 29 to both sides, and factor out -3) -3(x2 - 8x + 16) = -29 (divide by -3 to both sides) (x - 4)2 = 29/3 x - 4 = ± √(29/3) (add 4 to both sides) x = 4 ± √(29/3) (multiply by 3/3 inside the radical, if you want to rationalize the denominator) x = 4 ± (√87)/3
3x2 + 10x + 3 = (x + 3)(3x + 1).
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
3x2-24x-48 is not factorable.
No real roots.
3(2) + 24x + 48 = 0 6 + 24x + 48 = 0 24x + 54 = 0 24x + 54 - 54 = 0 - 54 24x = -54 24x/24 = -54/24 x = -9/4 x = -2 1/4
6x(3x2 - x + 4)
GCF = 12x.24x = 2(12x)36x3 = 3x2(12x)
3x(x - 8)
3x2 + 27x +60
3x2 + 24x + 48
3x2=6+38=44
3x2+26x+16 When factorised: (3x+2)(x+8)
3x2 + 10x + 3 = (x + 3)(3x + 1).