Q: How do you factor negative 16 plus 25 r squared?

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-2x2+32 -2(x2-16) -2(x+4)(x-4)

(b + 4)(b + 4)

2(x + 4)(x + 2)

x^2 + 10x + 16 = (x + 8)(x + 2)

(3x - 2)(x + 8)

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-2x2+32 -2(x2-16) -2(x+4)(x-4)

(b + 4)(b + 4)

2(x + 4)(x + 2)

x^2 + 10x + 16 = (x + 8)(x + 2)

(3x - 2)(x + 8)

(-4)^2 - ( - 2)^2 = Factor ((-4) + (-2))((-4) - (-2)) = (-4 -2)(-4 + 2) = (-6)(-2) = (+12) Or more simply 16 - 4 = (+12)

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

2(x - 2)(x - 4)

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

It can't be factored because its discriminant is less than zero.

Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2

Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)