Two is a prime factor of that equation.
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
x < 2 or x > 8.
x2-9x+8=0 has two solutions:x = 8x = 1
-22 = 4
Factor out -2: -2(x squared +11x-20). This is fully factored.
negative 2
Two is a prime factor of that equation.
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 1 plus or minus i where i is the square root of negative one.
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
no
-2*(-2)2 + 0*(-2) + 9 = -2*4 + 9 = -8 + 9 = 1
x < 2 or x > 8.
(x-1)(x+2)
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-1 plus or minus the square root of -3) divided by 2.x = -0.5 + 0.8660254037844386ix = -0.5 - 0.8660254037844386iwhere i is the square root of negative one.
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.