3r2(r - 4)(r2 + 4r + 16)
It is 4r + 12s
4r + 13 = 57subtract 13 from both sides:4r + 13 - 13 = 57 -134r = 44divide both sides by 4 to solve for r:4r/4 = 44/4r = 11
4r + 4 = 5r 4r - r = 3r 4r x r = 4r^2 4r/r = 4
-4r+6=14 isn't an inequality, its a linear equation. Anyway... -4r+6=14 (-6) -4r=8 (/4) -r=2 (x-1) r=-2
Since 81 - 16r^2 is a multiple of both 4 + r and 4 - r, it is automatically the LCM of this problem.
The equation for the volume of a cylinder is V = pi*r2*h. If you put the two hemispheres together, you have a sphere whose volume is V = (4/3)*pi*r3.So, V = (4/3)*pi*r3 + pi*r2*h = pi*r2*(4r/3 + h)
4r+3 = 3-2 4r = 3-3-2 4r = -2 Divide both sides of the equation by 4 to find the value of r: r = - 1/2
a + b + 4 is in its simplest form.
6x+4 factor: 2(3x+2)
Reduce, Reuse, Recycle and Rethink.